Question

Weight of ethane required to produces pressure of 1520mm when present in a 9litre vessel of 20

Answer 1

Answer:

Given that,

P=1520/760=2 atm

V= 9 liter and

T=293 K

Therefore,

PV=m/MRT

m=MPV/RT

=540/0.0821×293

=540/24.06

m =22.4 gram.

Weight of ethane is 22.4 gram.

Hope it helped!!