Question

Weight of nascent oxygen obtained from 6.32g kmno4 in acid medium??

Answer 1

Answer:

Weight of nascent oxygen obtained is 1.5996 g.

Explanation:

The reaction potassium permanganate in acidic medium to give nascent oxygen is given as:

$2KMnO_4+6H^+\rightarrow 2K^++2Mn^{2+}+3H_2O+5[O]$

Moles of $KMnO_4=\frac{6.32 g}{158.034 g/mol} =0.0399 mol$

According to reaction 1 mole of potassium permanganate gives 5 mole od nascent oxygen.

Then 0.0399 mol of potassium pemanganate will give:

$\frac{5}{2}\tiomes 0.0399=0.0999 mol$ of nascent oxygen

Mass of 0.0999 mol of nascent oxygen:

$0.0999 mol\times 16 g/mol=1.5996 g$

Weight of nascent oxygen obtained is 1.5996 g.