Question

Weight of oxalic acid to prepare m/20 solution in 250 ml

Answer 1

Explanation:

Its Molecular Wt. 126. Hence, to prepare 250 ml M/20 oxalic acid solution126*250/(20*1000) = 1.575 gram ofoxalic acid is to be dissolved in water in a250 ml volumetric flask.

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Answer 2

Answer:

The weight of oxalic acid to prepare m/20 solution in 250 ml is 6.3 gms.

Explanation and Calculation:

The general formula of oxalic acid is H₂C₂O₄, but in nature, oxalic acid remains in its crystalline hydrate form, which is H₂C₂O₄.2H₂O, so we will calculate the amount of oxalic acid required with respect to this hydrated form.

∴ The molecular weight of H₂C₂O₄.2H₂O= 126 gm/mol

This means that,

126 gm of oxalic acid in 1000 mL of solvent makes 1 (M) solution.

∴ 1000 mL of water contains 126 gm of oxalic acid.

∴ 250 mL solution of (M/20) strength will consist of

= $\frac{126}{1000}$× 250 × 0.20 gm of oxalic acid

= 6.3 gm of oxalic acid.

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