WEIGHT OF SCREW IS 0.2N. AREA IS 0.4×10∧-6 M∧2. FIND PRESSURE
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Answered by
6
Given :-
- Force (F) = 0.2N
- Area of screw (A) = 0.4 × 10^(-6)m²
To find :-
- Pressure
Solution :-
As we know that
→ Pressure = Force/Area
→ Pressure = 0.2/0.4 × 10^(-6)
→ Pressure = 2/4 × 10^(-6) × 10/10
→ Pressure = 1/2 × 10^(-6)
→ Pressure = 10⁶/2
→ Pressure = 10⁵ = 100000
Hence,
- Pressure = 10⁵ N/m²
Extra Information :-
- S.I unit of pressure is N/m² (Pascal)
- S.I unit of Force is Newton
- S.I unit of area is m²
Answered by
24
✴ Given :-
- Weight = 0.2 Newton.
- Area = (0.4 × 10)-⁶ m²
✴ To Find :-
- Pressure.
✴ Solution :-
We know that,
Pressure = Force/Area.
⇢ Pressure = 0.2/(0.4 × 10)-⁶
⇢ Pressure = 1/2 × 10-⁶
⇢ Pressure = 10⁵
Hence, Pressure = 100000 Newton/m².
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