Question

Weight of solute present in 500ml 0.2 n- h2so4 solution is

Answer 1

Normality=W/GEw *1000/V. 0.2=W/49 *1000/500 W=0.2*49/2=4.9gm GEw of H2SO4=Gmw/basicity.
=98/2
=49

Answer 2

Answer:

Explanation:

The formula is:-N=W/GEW×1000/V(in ml)

From the given data:-N=0.2,GEW=98/2=49

And V=500ml we have to find out the weight W=?

0.2=W/49×1000/500

0.2/2 =W/49

W=0.1×49

W=49