Chemistry, asked by AnushaNath4385, 1 year ago

%weight of zn in white vitriol is approximately equal to

Answers

Answered by AR17
0
Hello friend!!
White vitriol is ZnSO4
Weight of Zn = 65
Molecular weight of ZnSO4
= 65 ×1 + 32 × 1 + 16 × 4
=65 + 32 + 64
=161

Now %weight of Zn in ZnSO4
=( 65/161 ) × 100 = 40% (approx.)

HOPE IT HELPS..... :-)
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