Weighted arithmetic mean of first n natural numbers
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Step-by-step explanation:
So you are taking the sum of n X n / W
The weighted sum is the sum of the squares divided by W. The formula for the sum of the squares from 1 to n is n(n+1)(2+1)/6. That's a common formula, easy to look up, but you may not have seen it yet.
So your answer is
n(n+1)(2n+1)/6
-------------------- = (2n+1)/3
n(n+1)/2
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