Question

WELP HELP ME it maths

Answer 1

Answer:

x=120°

Step-by-step explanation:

∠AOB+∠BOC+∠COD+∠DOA=360°

95°+80°+x+65°=360°

240°+x=360°

x=360°-240°

x=120°

Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt In\: the \:given\: figure\: rays\: OA\:, OB\:, OC\: and\: OD\\\tt intersect\: at \:a \:point. \:Find\: the\: value \:of \:x$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf Rays\:OA\:, OB\:, OC\: and\: OD\:intersect at a point$
• $\sf \bf \angle BOA={95}^{\circ}$
• $\sf \bf \angle BOC={80}^{\circ}$
• $\sf \bf \angle DOA={65}^{\circ}$
• $\sf \bf \angle DOC={x}^{\circ}$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Find \:the \:value \:of \:x$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

$\sf \bf \implies \angle BOA+\angle BOC+\angle DOA+\angle DOC={360}^{\circ}$

$\sf \bf \implies {95}^{\circ}+{80}^{\circ}+{65}^{\circ}+x={360}^{\circ}$

$\sf \bf \implies {240}^{\circ}+x={360}^{\circ}$

$\sf \bf \implies x={360}^{\circ}-{240}^{\circ}$

$\implies{\boxed {\boxed {\color {blue} {\sf \bf x={120}^{\circ}}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

___________________________________________

$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

${\color {green} {\tt Identities}}$

$\sf \bf {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

$\sf \bf {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$\sf \bf (a+b) (a-b) ={a}^{2}-{b}^{2}$