Question

Wgen a resistance of 2 ohm is connected across the terminals of a cell the current is 0.5


a.when the resistance is increased to 5 ohm the current is 0.25


a.the internal resistance of the cell is

Answer 1

let   the  internal resistance be  r .
case 1 
E = I(r+R) = 0.5 (r + 2 )  = 0.5r + 1 
case 2 
E = I(r+R) = 0.25(r + 5 ) = 0.25 r + 1.25 

now , 
0.5 r  + 1 = 0.25 r  + 1.25
0.25r = 0.25
r = 1 ohm 
hope , it helps 

Answer 2

Answer:

hope this answers would help u