Question

Wh
0.2
2072 Set E Q.No. 9c A body of mass 2 kg is suspended from a
spring of negligible mass and is found to stretch the spring
0.1 m. What is its force constant and the time period? [4]
Ans: 0.628 sec​

Answer 1

Answer:force constant is 196 N/m

Time period is 0.628 sec

Explanation:

Answer 2

Given:

Mass of the body = 2 kg

extension in massless spring , x= 0.1m

To Find:

Find the force constant, k

Time period T

Solution:

tension developed in the spring = kx

                                                      =0.1k

Weight of the block = 2×9.8

                                 =19.6kgf

at equilibrium,

weight = tension

therefore, 19.8=0.1k

k=196N/m

T=2π√(m/k)

  =2×3.14×(√2/196)

  =0.628 sec

Hence the force constant is 196N/m and the time period is 0.628 sec.