Math, asked by diyainsh12109, 9 months ago

тнє whσ αnѕwєr ít fírѕt wíll вє mαrkєd αѕ вrαíníєѕt!!!!​

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Answered by Anonymous
12

\color{red}\large\underline{\underline{Question:}}

  • x^{2} + 5x + 6
  • x^{2} - 3x + 2
  • y^{2} - 11y + 24
  • 2x^{2} + x - 15

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\color{purple}\large\underline{\underline{To\:Find:}}

\underline{The\:Factorization\:of\:</p><p>the\:Equations}

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\color{blue}\large\underline{\underline{Concept:}}

\underline{By\:using\:middle-splitting\: theorem}

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\color{green}\large\underline{\underline{Solution:}}

  • x^{2} + 5x + 6

\Rightarrow x^{2} + (3 + 2)x + 6

\Rightarrow x^{2} + 3x + 2x + 6

\Rightarrow x(x + 3) + 2(x + 3)

\Rightarrow (x + 3)(x + 2)

\blue{\boxed{\therefore Ans\:is\:(x + 3)(x + 2)}}

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  • x^{2} - 3x + 2

\Rightarrow x^{2} - (2 + 1)x + 2

\Rightarrow x^{2} - 2x - 1x + 2

\Rightarrow x(x - 2) - 1(x - 2)

\Rightarrow (x - 2)(x - 1)

\blue{\boxed{\therefore Ans\:is\:(x - 2)(x - 1)}}

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  • y^{2} - 11y + 24

\Rightarrow y^{2} - (8 + 3)y + 24

\Rightarrow y^{2} - 8y - 3y + 24

\Rightarrow y(y - 8) - 3(y - 8)

\Rightarrow (y - 8)(y - 3)

\blue{\boxed{\therefore Ans\:is\:(x - 8)(x - 3)}}

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  • 2x^{2} + x - 15

\Rightarrow 2x^{2} + (6 - 5)x - 15

\Rightarrow 2x^{2} + 6x - 5x - 15

\Rightarrow 2x(x + 3) - 5(x + 3)

\Rightarrow (x + 3)(2x - 5)

\blue{\boxed{\therefore Ans\:is\:(x + 3)(2x - 5)}}

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Answered by Anonymous
6

\huge\mathfrak\color{red}{Answer}

\rule{200}3

1 {x}^{2}  + 5x + 6

 {x}^{2}  + 3x + 2x + 6

x(x + 3) + 2(x + 3)

(x + 3)(x + 2)

\rule{200}3

2 {x}^{2}  - 3x + 2

 {x}^{2}  - x - 2x + 2

x(x - 1) - 2(x - 1)

(x - 1)(x - 2)

\rule{200}3

3 {y}^{2}  - 11y + 24

 {y}^{2}  - 3y - 8y + 24

y(y - 3) - 8(y - 3)

(y - 3)(y - 8)

\rule{200}3

4 {2x}^{2}  + x - 15

 {2x}^{2}  + 6x - 5x - 15

2x(x + 3) - 5(x + 3)

(x + 3)(2x - 5)

\rule{200}3

&lt;body bgcolor=white&gt;&lt;marquee direction="up"&gt;&lt;font color=red&gt;hope it helps you.....

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