Whɑt is the time ɑnd position when theif is cɑught if the ɑccelerɑtion of theif is 1m/s^2 ɑnd the speed of the police is 20m/s ɑnd distɑnce between them is 150m .
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Answers
Answered by
9
Answer:
The relative velocity of policeman w.r.t. thief
=10−9=1 ms
−1
∴ Time taken by police to catch the thief
= velocityx distance
= 1 x100
=100 s.
Answered by
1
Answer:
100
hope it helps you
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