Question

Whai is relation between intensity and phase difference??

Answer 1

A general representation of Young's double slit experiment looks like,

Now coming to formula, the relation between average intensity of light fringes observed on the screen (I) and path difference between the two waves (sinθd)(sin⁡θd) emerging from both the slits is,

I=Imaxcos2I=Imaxcos2πdsinθλπdsin⁡θλ

where Imax=Imax= maximum intensity on the screen (i.e. intensity of the central fringe)

θθ can be calculated as represented in the image.

For small values of θθ, sinθsin⁡θ ~ yLyL. So the above equation can be written as,

I=Imaxcos2(πdλ⋅yL)I=Imaxcos2(πdλ⋅yL)

That's all there is regarding to relation between path difference and intensity of light in Young's double slit experiment.

Hope you find it helpful. Happy physicsing!❤