Question

whan a 12 V battery is connected across an unknown resistor,there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.

Answer 1

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According to Ohm’s law,

V = IR ⟹

=v/I

Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore,

=12/ 0.0025 = 4800 Ω = 4.8 kΩ

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Answer 2

4.8 KΩ

Given:

Potential Difference (V) = 12 V

Current that is there in the circuit (I) = 2.5 mA

Converting the current in milliampere  to Amperes by multiplying by 10^-3:

= 2.5 x 10^-3 Amperes

To Find:

Resistance of the resistor.

Calculating:

Ohm's law tells us:

V = IR

Taking I to the other side of the equation we get:

R = V / I

Substituting all the values that are known to us in this formula we get:

R = 12 / 2.5 x 10^-3

R = 4.8 x 10^3

(When 10^-3 goes from the denominator to the number the power -3 will become positive)

R = 4.8 K

Ω

K

Ω  here is Kilo ohms. 1 kilo ohm = 1000 ohms/

Hence, after calculating we get the resistance of the resistor to be 4.8 KΩ

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