Math, asked by cosmicdagger5, 11 months ago

whar will be (1+tan^2)/cos^2

Answers

Answered by helloman2174

0

sec^2/cos^2=sec/cos=1/cos×cos/1=1

Answered by Amankumar2newton

0

Step-by-step explanation:

1+tan^2/cos^2

=sec^2/cos^2

=sec^2×sec^2

=sec^4

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