Math, asked by cosmicdagger5, 1 year ago

whar will be (1+tan^2)/cos^2 ​

Answers

Answered by helloman2174
0

sec^2/cos^2=sec/cos=1/cos×cos/1=1

Answered by Amankumar2newton
0

Step-by-step explanation:

1+tan^2/cos^2

=sec^2/cos^2

=sec^2×sec^2

=sec^4

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