Math, asked by nesthangam, 1 year ago

What 3 consecutive even numbers have a sum of  246

Answers

Answered by ctinamaria31
37
x
x+2
x+4

x+x+2+x+4=246
3x+6=246
3x=246-6
3x=240
x=240:3
x=80

so the numbers are 80 82 84

80+82+84=246
Answered by mysticd
4

Answer:

Required three consecutive even numbers are 80,82 and 84

Step-by-step explanation:

Let x ,(x+2) and (x+4) are three consecutive even numbers.

According to the problem given,

Sum of these numbers = 246

=> x+x+2+x+4 = 246

=> 3x + 6 = 246

=> 3x = 246 - 6

=> 3x = 240

/* Divide each term by 3, we get

=> x = 80

Therefore,

Required three consecutive even numbers are

x = 80,

x + 2 = 80 + 2 = 82 ,

x + 4 = 80 + 4 = 84

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