What 4 consecutive even integers whose sum is 140?
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HERE IS YOUR ANSWER -
x + ( x +2 ) + ( x+4 ) + ( x +6 ) = 140
4x + 12 = 140
4x = 140 - 12
4x = 128
x = 128/4
x = 32
1st number = 32
2nd number = ( 32 + 2 ) = 34
3rd number = ( 32 + 4 ) = 36
4th number. = ( 32 + 6 ) = 38
HENCE THE FOUR CONSECUTIVE NUMBER ARE
32 , 34 , 36 and 38
HOPE IT HELPS YOU...
x + ( x +2 ) + ( x+4 ) + ( x +6 ) = 140
4x + 12 = 140
4x = 140 - 12
4x = 128
x = 128/4
x = 32
1st number = 32
2nd number = ( 32 + 2 ) = 34
3rd number = ( 32 + 4 ) = 36
4th number. = ( 32 + 6 ) = 38
HENCE THE FOUR CONSECUTIVE NUMBER ARE
32 , 34 , 36 and 38
HOPE IT HELPS YOU...
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