what a^2 and b^2 in the following problem
a^2+ b^2= 7^2
a^2+ b^2= 49
Anonymous:
a = 0 and b = 7 OR b = 0 and a = 7
Answers
Answered by
2
sorry your question is wrong!
U don't know how to solve it
49 is a Pythogorean triplet
Ohk
fine
Thanks
0^2 + 7^2 = 49. 0 is still a natural number and there is no requirement that a > 0 and b > 0.
Answered by
0
Answer:........???
Step-by-step explanation:
Solving
a2 + b2 = 49
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '-1b2' to each side of the equation.
a2 + b2 + -1b2 = 49 + -1b2
Combine like terms: b2 + -1b2 = 0
a2 + 0 = 49 + -1b2
a2 = 49 + -1b2
Simplifying
a2 = 49 + -1b2
Reorder the terms:
-49 + a2 + b2 = 49 + -1b2 + -49 + b2
Reorder the terms:
-49 + a2 + b2 = 49 + -49 + -1b2 + b2
Combine like terms: 49 + -49 = 0
-49 + a2 + b2 = 0 + -1b2 + b2
-49 + a2 + b2 = -1b2 + b2
Combine like terms: -1b2 + b2 = 0
-49 + a2 + b2 = 0
The solution to this equation could not be determined.
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