Question

What a volume of oxygen gas measured at s.t.p will be produced during electrolysis by current of 5a supplied for 30 minutes

Answer 1

Explanation:

Current, I=1A

Time, t=16 min 5 sec= 965 seconds

n=2

Cu

+2

+2e

−

⟶Cu

4OH

−1

⟶O

2

+2H

2

O+4e

−1

W=

nF

I×t×M

⇒W=

2×96500

1×965×63.5

⇒W=0.3175g

2×63.5g⟶22.4 litreO

2

⇒0.3175g⟶

63.5×2

0.3175

×22.4

Volume of gas liberated during electrolysis = 56 ml