Math, asked by jadavgautam207, 1 day ago

What amount Harish has to pay at the end of 2 years on sum of Rs 40000 at an
interest rate of 16% compounded annually?
with steps

Answers

Answered by mokshjoshi
2

Answer:

40,000, R = 16%, n = 2. Amount paid by Harish at the end of 2 years is Rs. 53,824.

Answered by kumaranshusingh2807
2

Answer:

40,000, R = 16%, n = 2. Amount paid by Harish at the end of 2 years is Rs. 53,824.

Step-by-step explanation:

We know that, formula for compound interest,

A = P(1+R100)n

Where, P = principle

N = no. of years

P = Rs. 40,000, R = 16%, n = 2.

A = 40000(1+16100)2

A = 40000(1+0.16)2

A = 40000(1.16)2

A = 40000 × 1.3456

A = Rs. 53,824

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