Question

What amount of bromine will be required to convert 2 gm of phenol to tri bromo phenol

Answer 1

Phenol +3Br2=tribromophenol +3HBr

Answer 2

Answer: Amount of bromine required is 10.163 grams.

Explanation:

The reaction of phenol with bromine in aqueous medium produces 2,4,6-tribromo phenol.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}[\text{Molar mass}}$      .....(1)

For phenol:

Given mass = 2 g

Molar mass = 94.11 g/mol

Putting values in above equation, we get:

$\text{moles of phenol}=\frac{2g}{94.11g/mol}=0.0212mol$

The chemical equation for the reaction follows:

$\text{Phenol}+3Br_2\xrightarrow[]{H_2O} \text{2,4,6-tribromo phenol}$

By Stoichiometry of the reaction:

1 mole of phenol reacts with 3 moles of bromine gas.

So, 0.0212 moles of phenol will react with = $\frac{3}{1}\times 0.0212=0.636mol$

Now, using equation 1:

Molar mass of bromine gas = 159.8 g/mol

Number of moles = 0.0636 mol

[tex]0.0636mol=\frac{\text{Mass of bromine gas}}{159.8g/mol}\\\\ \text{Mass of bromine gas}=10.163g[/tex]

Hence, amount of bromine required is 10.163 grams.