What amount of CaCO3 is required to completely react with 25ml of 0.75M
HCl
CaCO3 +2HCl=CaCl2 + H2O + CO2
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Molarity of HCl = 0.75 mol/L
Volume of HCl = 25ml = 0.025L
Moles of HCl = MX V = 0.75 x 0.025 = 0.01875 mol
2 mol of HCl react with 1 mole of CaCO3
1 mole of HCl react with 1/2 mole of CaCO3
0.01875 moles of HCl will react with 0.01875/2 = 0.009375 moles of CaCO3.
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