Question

What amount of calcium carbonate will react with excess dilute HCL to produce 66g CO2

Answer 1

Answer:

150 g

Explanation:

CaCO₃   +      2HCL ───────► CaCL₂      +        H₂O       +         CO₂

44 g CO₂  ≡  100 g  CaCO₃  

66 g CO₂  ≡  (100/44)×66 g  CaCO₃ = 149.999 ≈ 150 g

Answer 2

Reaction:-

caco3+2HCL=cacl2+H2O +co2

1mole of caco3 gives 1mole of CO2

atomic mass of caco3=40+(12+48)g/mole=100g/mole

100g/mole mass of caco3 is correspond to 100g/mole/100g=1mole of caco3

Atomic mass of CO2=44 g/mole

44g/mole of CO2=100g/mole of caco3

or,1g of CO2= 100/44 g of caco3

or,66g of CO2=100/44×66 g of caco3

or,66g of CO2=150g of caco3

so 150g of calcium carbonate will react with excess dilute HCL to produce 66g CO2