What amount of carbon dioxide at n.t.p evolved by strong heating of20 gram of calcium carbonatr?
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As 100 gram of caco3 gives 24 dm3 at ntp
So 1 gram give 24÷ 100 dm3 of co2
And 10 gives 24× 10 ÷ 100 dm3 of co2 at ntp
= 2.4 dm3
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So 1 gram give 24÷ 100 dm3 of co2
And 10 gives 24× 10 ÷ 100 dm3 of co2 at ntp
= 2.4 dm3
Hope it helps you ...
If it is helpfull to you then plzz mark me as brainlist. ..
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