What amount of carbon dioxide (in mol) will be formed when 32.0 g of methane, CH4,
burns completely in oxygen?
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0
Answer:
the amount of carbon dioxide it squared away from velocity
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Answer:
Balanced equation:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
1mol CH4 reacts with 2 mol O2 to produce 1 mol CO2
Molar mass O2 = 32g/mol
Molar mass CH4 = 16g/mol
Molar mass CO2 = 44g/mol
16g CH4 will react with 64g O2 to produce 44g CO2
There is only 32g O2 available
8g CH4 will react with 32g O2 to produce 22g CO2
Answer: 22g CO2 produced.
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