what amount of carbon dioxide is generated by the reaction of 10 gm CaCo3 with excess Hydrochloric acid ? [ H= 1 , Cl = 35.5 ] ( answer= 4.4 gm )
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CaCO3+2HCl to CaCl2+CO2+H2O balance equation and coefficient of calcium carbonate and carbon dioxide so mole of CaCO3 is equal to the mole of CO2 ,,, mole of CaCO3 is 10/100 = 0.1 and so 0.1= wieght / molar mass of CO2 ,,, 0.1= weight/44 after solving 4.4 gm ans
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