Question

What amount of dioxygen (in gram) contains
1.8 × 10²² molecules?
(A) 0.0960
(B) 0.960
(C) 9.60
(D) 96.0

Answer 1

6.022 × 10^22 dioxygen molecules are present in 1 mole i.e 32 g of oxygen. 1.8 × 10^22 dioxygen molecules will be present in 1.8 × 10^22 × 32/6.022 × 10^22 =
0.96 g of dioxygen

Answer 2

Hello Raaj,

● Answer -
(B) 0.96 gm

● Explanation -
1 mol of oxygen contains 6.022×10^23 molecules.

Here, moles of oxygen can be calculated by
n = (1.8×10^22) / (6.022×10^23)
n = 0.03 moles

Mass of given moles of Oxygen is calculated by -
W = M × n
W = 32 × 0.03
W = 0.96 g

Therefore, 0.96 gm of O2 contains 1.8×10^22 molecules.


Hope this helped you. Keep asking..