what amount of heat is required to change 10 gm water at T=30 Celsius into the vapour at 110 Celsius
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Q (heat energy)=Mass (m)×c (specific heat capacity)× change in temperature
Q=10 gm×4.2J/gm/K×(110-30)°C
Q=10×4.2×90
Q=3780 J
Q=10 gm×4.2J/gm/K×(110-30)°C
Q=10×4.2×90
Q=3780 J
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