what amount of hydrogen sulphide will be obtained on reaction of 4.4g ferrous sulphide with excess hcl
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The ratio of the weight of iron and sulphur in the first sample of the compound is Fe:S::0.7:0.4 or 7:4.
According to the second experiment, 2.8g or iron gives 4.4g ferrous sulphide, or 2.8gFe combines with S=4.4−2.8=1.6g
Therefore, the ratio of the weights of Fe:S::2.8:1.6 or 7:4.
Since the ratio of the weights of the two elements is same both the cases, the law of constant composition is true.
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