Question

What amount of ice will remain when 52g Ice is added to 100 g of water at 40 degree Celsius. Specific heat of water is 1 cal/g and latent heat of fusion ofe ice is 80 cal/g

Answer 1

Answer:

ismein 50 kg aaj de rakhi hai 50 gram aur sau gram water joda ja raha hai 40 degree Celsius per square feet iski 1 calorie upon hai aur future of rs 80 kilogram de rakha hai isko Hindi mein samjha Diya English mein kariye

Answer 2

Phenomena Used is Heat Gained = Heat Lost

Explanation:

Let m be mass of melted ice & temperature of ice be t.

Specific Heat of Water = $1\ calg^-^1 C$

Specific Heat of Ice = $0.5\ calg^-^1 C$

Latent Heat of Fusion of Ice = $80\ calg^-^1$

Heat Gained by Ice = Heat Lost by Water

Hence,

$Mass\ of\ Ice \times Latent\ Heat + Mass\ of\ Ice\ whose\ temperature\ is\ raised \times specific\ heat \times rise\ in\ temperature = Mass\ of\ Water \times Specific\ Heat \times fall\ in\ temperature$

$m \times 80 + 52 \times 0.5 \times t = 100 \times 1 \times 40$

$80m + 26t = 1400$

$m = \frac {1400 - 26t}{80}$

Finally after solving, m being calculated from the mass (52 g), and thereby getting (amount) Mass of ice.