Question

What amount of pure Magnesium carbonate is required to make a reaction with dilute HCl at 27°C and 750 mm Hg to produce 1L CO2 ? [Mg = 24, C= 12, O = 16]​

Answer 1

Answer:

CaCo3+2HCL__CaCl2+H2O+Co2

100g 1mole 22.4L

44g 1mole 22.4L

we know that 1mole of any gas 0°C and 1atm pressure occupies 22.4L volume

so 100g CaCo3 forms 22.4L of Co2

hence , 2.5g CaCo3 will formed=2.5×22.4 /100=56/100Lof Co2

0.56L of Co2