" What amount of solute must be taken in 200gm of watoon to form a solution with 10% mass by mass freinage
Answers
Answer:
As we are being provided with the value of the weight of the solution which is equal to 200 g. The question says that the weight of the solute is equal to 10 % of 200. This means is equal to 20 g.
- We have to find the weight percentage of solute precipitate (x). Therefore, we can write the solute remained will be 20 - x.
- The concentration of the remaining solution becomes 6 %. We can write the weight of solution remained is = 200 - x
- We will find the Mass percent of solute which is given by the formula that is mass of solute divided by the mass of solution, then whole multiplied by 100.
Mass percent = m solutemsolution×100
By substituting the values we have,
6% = 20−x200−x×100
⇒2000−100x=1200−6x
Thus, by simplifying the above equation, the value of x will be,
94x=800
⇒x=8.51g
- Hence, we can conclude that the mass of the precipitated solute is 8.51 gm.
Explanation:
In the lower classes, we have studied the calculations of basic entities like mass percent, the molecular weight of the chemicals, and many others. Let us see in detail the calculation of mass percent of the given solute.
- As we are being provided with the value of the weight of the solution which is equal to 200 g. The question says that the weight of the solute is equal to 10 % of 200. This means is equal to 20 g.
- We have to find the weight percentage of solute precipitate (x). Therefore, we can write the solute remained will be 20 - x.
- The concentration of the remaining solution becomes 6 %. We can write the weight of solution remained is = 200 - x
- We will find the Mass percent of solute which is given by the formula that is mass of solute divided by the mass of solution, then whole multiplied by 100.
Mass percent = msolutemsolution×100
By substituting the values we have,
6% = 20−x200−x×100
⇒2000−100x=1200−6x
Thus, by simplifying the above equation, the value of x will be,
94x=800
⇒x=8.51g
- Hence, we can conclude that the mass of the precipitated solute is 8.51 gm.
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