Question

What amount of sulphuric acid will be required to dissolve

3 g of magnesium carbonate?

MgCO3

+ H2SO4 ⟶ MgSO4

+ H2O + CO2

[Mg = 24, C = 12, S

= 32, O = 16]​

Answer 1

Answer:

Explanation:

1 mole mgco3 require 2 mole HCl so 1mole mgco3 contain 84 grams so 84g react with 73 g HCl so 4.2 grams require 3.65 grams HCl

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