What amount of water produced by combustion of 16g of methane?
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Answer:
The amount of water produced by the combustion of 16 gram methane is 36 grams
Answered by
0
Answer:
36g
Explanation:
The chemical reaction, that occurs is :-
CH4 +2O2 ––––> CO2+2H2O
We see that one mole of CH4 produces two moles of water on combustion.
mass of CH4 available = 16g
molar mass of CH4 = 16g
So, moles of CH4 = given mass/molar mass = 16g/16g = 1 mole.
So , moles of H2O produced = 2(moles of CH4)
moles of H2O = 2×1 = 2
Molar mass of H2O = 18 g
Mass of H2O produced = moles of H2O × molar mass of H2O = 2×18g = 36g ( Ans )
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