what amount of water should be added to 500ml of 2 molar HCl solution to get 0.5M solution
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To begin solving this problem, we'll start with the theory of molar equivalence i.e. M1*V1 = M2*V2 where M1, M2 and V1, V2 represent the initial and final molarities and volumes respectively.
Now, we started off with 500 mL of 2 M HCl solution and need to attain 0.5M concentration.
Hence,
2M * 500 mL = 0.5M * V
or, V = (2M * 500 mL)/0.5M
or, V = 2000 mL
Thus, for the HCL concentration to be 0.5M, we need 2000 mL of the solution. Since we already have 500 mL of the 2M HCL concentrate, we need to add 1500 mL to achieve what we set out for.
Now, we started off with 500 mL of 2 M HCl solution and need to attain 0.5M concentration.
Hence,
2M * 500 mL = 0.5M * V
or, V = (2M * 500 mL)/0.5M
or, V = 2000 mL
Thus, for the HCL concentration to be 0.5M, we need 2000 mL of the solution. Since we already have 500 mL of the 2M HCL concentrate, we need to add 1500 mL to achieve what we set out for.
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