Question

What amount of Zinc dust is required to produce 7g hydrogen ? Zinc dust contains 88% Zinc(Zn = 65.5).​

Answer 1

Answer:

Explanation:

Zn(s)+2HCl(aq)→ZnCl  2  (aq)+H  2  (g)

1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of hydrogen.

one mole of Zn(s) produces one mole of H2(g). So 457.7g of Zn will produce  7 g of H2(g).

Mass of 1 mol Zn = 1 mol * 65.39g/mol = 65.39g Zn required to produce  1 g hydrogen

then 7g hydrogen is produced by zinc = 7 ×65.39g = 457.73 grams  of zinc

Answer 2

Answer:

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