Question

what amount should be returned on a loan of Rs.12000 for 2 years at the rate of 6%​

Answer 1

Step-by-step explanation:

Principal = ₹12000

Rate of interest = 6%

Time = 2 years

S.I. = P×R×T/100

S.I. = 12000×6×2/100

$\frac{12000 \times 6\times 2}{100}$

$120 \times 6 \times 2$

$120 \times 12$

$1440$

Hence, S.I. = Rs. 1440

Amount = S.I. + Principal

Amount = ₹1440 + ₹12000 = ₹13440

Amount = ₹13440

The amount should be returned on the loan is ₹13440.

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Answer 2

Answer:

₹13440

Step-by-step explanation:

Principal = ₹12000

Rate of interest = 6%

Time = 2 years

S.I. = P×R×T/100

S.I. = 12000×6×2/100

\frac{12000 \times 6\times 2}{100}

100

12000×6×2

120 \times 6 \times 2120×6×2

120 \times 12120×12

14401440

Hence, S.I. = Rs. 1440

Amount = S.I. + Principal

Amount = ₹1440 + ₹12000 = ₹13440

Amount = ₹13440