Question

what amount silver chloride is formed by action of 5.8 50 gram of sodium chloride all and excess of silver nitrate​

Answer 1

Explanation:

NaCl is limiting reagent

Amount of product , i.e AgCl depends on limiting reagent NaCl

1 mole of NaCl gives 1 mole of AgCl

molar mass of NaCl is 58.5

no of moles of NaCl available is 5.85/58.5 = 0.1

so 0.1 mole of AgCl will be formed

molar mass of AgCl is 143.5

so no. of moles * molarmass = mass

mass= 143.5*0.1

= 14.35g