Question

what angle is formed by hands of a clock at 7:10​

Answer 1

Answer:

The angle between the lines joining (7 to centre of the Dial) & (2 to centre of the Dial) = 150° + 60° = 210° along the upper-side, Or, 210° - 60° = 150° on the lower side. Movement of the Hour-hand while the Minute-hand moves from 12 to 2 = 30° × (60°/360°) = 30°/6 = 5°.

Answer 2

Answer:

Use the formula of FINDING Angle between Minute Hand and Hour Hand at time h:m (means, h hour m minutes)

Angle = (11/2)m - 30h [when minute hand is ahead of hour hand]

OR

Angle = 30h - (11/2)m [when hour hand is ahead of minute hand],

here the position of hands are consider from the number 12 on clock.

At 7:10, the hour hand is ahead of minute hand, so put h = 7 and m = 10 in

Angle = 30h - (11/2)m = 30 x 7 - (11/2)x10 = 210 - 55 = 155 degree.

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