What angle will be formd betwn the hands of teclock at 3.30?
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Here u have to remember a formula this kind of problems.
β = |30h-11m|/2
where β is the angle between hors and minutes hand.
h is hours and m is minuites
here we need to find angle at 3:30
β=|30(3)-11(30)|/2
β=75 which is angle between two hands at 3:30
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