Math, asked by sunitasingh6751, 19 hours ago

What approach we have to take in solving these type of questions.

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Answers

Answered by yamyagole4003
0

Answer:

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Answered by qwerty1123
1

ANSWER:

x^8-y^8

=(x^4)^2−(y^4)^2                  [a^2−b^2=(a+b)(a−b)]                    

         =(x^4+y^4)(x^4−y^4)  

        =(x^4+y^4)[(x^2)^2−(y^2)^2]    

        =(x^4+y^4)(x^2+y^2)(x^2−y^2)    

        =(x^4+y^4)(x^2+y^2)(x+y)(x−y)

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