What are all the real zeroes fo y=(x-12)^3-7?
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Real zeros means the roots o the equation.
Roots of the equation can be found by making y=0 and solving the equation
So when y=0
0=(x-12)^3-7
X^3+36x^2+432x-1735=0
Roots of the equation can't be found algebraically so by numerically X=13.912931
Roots of the equation can be found by making y=0 and solving the equation
So when y=0
0=(x-12)^3-7
X^3+36x^2+432x-1735=0
Roots of the equation can't be found algebraically so by numerically X=13.912931
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