Math, asked by ganeshshelke469, 1 year ago

What are conditions for cubic polynomial have 3 real roots?

Answers

Answered by anil161016
0

Answer:

a + b + c = - b/a

ab + bc + ca = c/a

abc = - d/a

Answered by SrijanShrivastava
1

For a Cubic Equation :

f(x) = a {x}^{3}  + b {x}^{2}  + cx + d = 0

 \forall  \:  \: x_{1,2,3} \in \: ℝ

The Condition For All Real Roots to Occur :

  \sf{b}^{2} {c}^{2}  +  18abcd - 27 {a}^{2}  {d}^{2}  - 4a {c}^{3}  - 4 {b}^{3} d > 0

All the Roots of the Cubic Are :

 \sf \: x_{1,2,3} =  \frac{ - b  \:  +  \:2  \sqrt{ {b}^{2} - 3ac } \cos( \frac{1}{3} \arccos [  \frac{9abc - 2 {b}^{3}  - 27 {a}^{2} d}{2( {b}^{2}  - 3ac) \sqrt{ { {b}^{2}  - 3ac} } } ]   +  \frac{2k\pi}{3} )   }{3a}

where,

k \in  (0,1,2)

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