Question

What are factors of 3x2-8x-16

Answer 1

Answer:

the factors are 4 and -4/3

Answer 2

$Given \: Quadratic \: polynomial : \\3x^{2} - 8x - 16$

/* Splitting the middle term,we get */

$= 3x^{2} + 12x - 4x - 16 \\= 3x( x + 4 ) - 4( x + 4 ) \\= ( x + 4 )( 3x - 4 )$

Therefore.,

$\red{ Factors \: of \: 3x^{2} - 8x - 16 }$

$\green { = ( x + 4 )( 3x - 4 )}$

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