what are methods to solve quadratic equation
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Answered by
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1. Middle term splitting
x²+7x+10=0
x²+5x+2x+10=0
2. Hit and trial method
By putting different values in place of x until the equation is equal to 0.
3. Discriminant formula
Here, x= - b +root D /2a
And x = - b - root D/2a
Thank you...
x²+7x+10=0
x²+5x+2x+10=0
2. Hit and trial method
By putting different values in place of x until the equation is equal to 0.
3. Discriminant formula
Here, x= - b +root D /2a
And x = - b - root D/2a
Thank you...
Swathi01:
The methods are
Answered by
2
Step-by-step explanation:
Well, there are following two methods for solving quadratic equation:-
1. By Factorisation method:-
If ax² + bx + c can be factorised as ( x - α ) ( x - β ) then ax² + bx + c = 0 is equivalent to (x - α) (x - β) = 0
Thus, (x - α) (x - β) = 0
(x - α) = 0 or (x - β) = 0
x = α or x = β
Here, α and β are called roots of equation ax² + bx + c = 0
2. By Sridharacharya's Method:-
Using quadratic formula, write the quadratic in the standard form ax² + bx + c = 0 then roots are,
α = - b + √b² - 4ac / 2a , β = - b - √b² - 4ac / 2a
Here, D = b² - 4ac is called the 'discriminant' of quadratic equation.
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