what are no. of atoms present in 64g of sulphur dioxide?
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molar mass of S8 is 32x8= 256g
number of moles in 64g of S8 = given mass / molar mass= 64/256= 0.25 moles
now we know the number of atoms in one mole mass = 6.02*10^23
so. the number of atoms in 0.25 moles of S8= 0.25 * 6.02*10^23=1.505 * 10^23 atoms
number of moles in 64g of S8 = given mass / molar mass= 64/256= 0.25 moles
now we know the number of atoms in one mole mass = 6.02*10^23
so. the number of atoms in 0.25 moles of S8= 0.25 * 6.02*10^23=1.505 * 10^23 atoms
mohitgmgoel:
sulphur dioxide formula is SO2
ya he did it wrong
but my one is correct
sorry it is of 64g of sulphur
dioxide
Answered by
1
mole=64/64= 1 mole
NO. of atoms = 1 Na= 6.022× 10^23
NO. of atoms = 1 Na= 6.022× 10^23
Read the question properly....
is it wrong
mine is wrong
four option a] 24.088 x 10^23
b] 12.044 x 10^23
c}18.198 x 10^23
d} none of option your answer is wrong
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