what are session courts??
Answers
Answer:
Given :-
The digits in the tens place of a two digit number is three times that in the units place.
The digits are reversed the new will be 36 less than the original number.
To Find :-
What is the original number.
Solution :-
Let,
\mapsto↦ The digits in the one's place be x
\mapsto↦ The digits in the ten's place will be 3x
Hence,
\dashrightarrow⇢ The original number will be :
\implies \sf 10 \times 3x + x⟹10×3x+x
\implies \sf 30x + x⟹30x+x
\implies \sf\bold{\purple{31x}}⟹31x
According to the question :
\implies \sf 30 + x - 36 =\: 10x + 3x⟹30+x−36=10x+3x
\implies \sf 31x - 36 =\: 13x⟹31x−36=13x
\implies \sf - 36 =\: 13x - 31x⟹−36=13x−31x
\implies \sf \cancel{-} 36 =\: \cancel{-} 18x⟹
−
36=
−
18x
\implies \sf \dfrac{\cancel{36}}{\cancel{18}} =\: x⟹
18
36
=x
\implies \sf 2 =\: x⟹2=x
\implies \sf\bold{\purple{x =\: 2}}⟹x=2
Hence, the required original number is :
\leadsto \sf 31x⇝31x
\leadsto \sf 31(2)⇝31(2)
\leadsto \sf 31 \times 2⇝31×2
\leadsto\bold{\red{62}}⇝62
\therefore∴ The original number is 62.