What are the 2 consecutive integers for 130
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Answer:
x2 + (x + 2)2 = 130
x2 + x2 + 4x + 4 = 130
2x2 + 4x + 4 = 130
divide above by 2:
x2 + 2x + 2 = 65
x2 + 2x - 63 = 0
(x + 9)(x - 7) = 0
x = -9, or 7
since we need positive numbers, it's 7, 9
hope it helped you .Mark me
Answered by
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Answer:
answer is 64 and 66
hope answer is correct
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