Question

What are the co ordinates of the point of intersection of the lines x+3y=7and 2x+y=-1 answer

Answer 1

Answer:

hey mate!!

Step-by-step explanation:

first equation,

x+3y=7

3y=7-x

y=7-x/3

let x be 1

then,

y=7-1/3

=6/3

=2

now, (x, y) =(1,2)-1st quadrant

let x be 4,then,

y=7-4/3

=3/3

=1

now, (x, y) =(4,1)-1st quadrant

let x be 7

then, y=7-7/3

=0/3

=0

now,(x, y) =(7,0)-x axis

let x be 10

y=7-10/3

=-3/3

=-1

now, (x, y) =(10,-1)-4th quadrant

second equation,

2x+y=1

2x=1-y

x=1-y/2

let y be 1

x=1-1/2

=0

now, (x, y) =(0,1)-y axis

let y be 3

x=1-3/2

=-2/2

=-1

now, (x, y) =(-1,3)-2nd quadrant

let y be 5

x=1-5/2

=-4/2

=-2

now,(x, y) =(-2,5)-2nd quadrant

let y be 7

x=1-7/2

=-6/2

=-3

now, (x, y) =(-3,7)-2nd quadrant

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