Question

what are the complete factors of 8b³+27c³​

Answer 1

Answer:

Theory : A sum of two perfect cubes, a3 + b3 can be factored into :

(a+b) • (a2-ab+b2)

Proof : (a+b) • (a2-ab+b2) =

a3-a2b+ab2+ba2-b2a+b3 =

a3+(a2b-ba2)+(ab2-b2a)+b3=

a3+0+0+b3=

a3+b3

Check : 8 is the cube of 2

Check : 27 is the cube of 3

Check : b3 is the cube of b1

Check : c3 is the cube of c1

Factorization is :

(2b + 3c) • (4b2 - 6bc + 9c2)

Answer 2

Answer:

(2b+3a)(4b^2-6ab+9a^2)

Step-by-step explanation:

8b^3 +27c^3

is of the form a^3+b^3

(2b+3a)(4b^2-6ab+9a^2)